B(n)=-8-2(n-1) find the 9th term in the sequence

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Step-by-step explanation:

We are given that

We have to find the 9th term in the sequence.

Substitute n=1

Then, we get

Substitute n=2

Then,we get

b(2)=-8-2(2-1)=-8-2=-10

n=3

b(3)=-8-2(3-1)=-8-4=-12

When the difference  between two consecutive terms is constant then, the sequence is called arithmetic sequence.

Therefore, the given sequence is in A.P

The nth term of A.P is given by

We have,

n=9

Substitute the values in the formula

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