Find the minimum length of u × v when u = 5 j and v is a position vector of length 4 in the xy-plane.

Length 8 that starts atthe origin and rotates in the xy-plane. Find the maximumand minimum values of the length of the vector u× v.

First step is to get rid of the square root. remember that a square root is the same as raising to the (1/2) power. see below: multiply exponents per exponent rules to get: remember you subtract exponents from the denominator and add exponents in the numerator so: simplify further: so a is the correct choice. if you don't understand this google exponent rules and it will you understand. look at the image results.