Rewrite the following fractions as division problems. a. 7⁄11 b. 5⁄2 c. 9⁄10 d. 7⁄15

To rewrite the fractions as a division problem, use the denominator to divide the numerator. The denominator is the number below while the numerator is the number above.
1. For 7/11
Proceed as follows:
How many time will you find 11 in 7? This is not possible, so you will write down zero and put a decimal point in front of it. Then add zero at the back of 7 to get 70. How many time will 11 go in 70? That will be 6 times and you will have 4 remaining. Add zero to the back of the 4 to get 40. How many time will 11 go in 40? That will be 3 times and 7 will remain. You can continue to add zero to the remainder until you get as many decimal place as you desired.
From the calculations done above the answer we have obtained is 0.63.
Therefore, 7/11 = 0.63.

2. For 5/2, the same principle is applicable.
How many times will 2 go in 5? That will be 2 times remaining 1. Add zero to that one to obtain 10. How many times will 2 go in 10.That will be 5 times remaining zero.
Therefore 5/2 = 2.50.

3. For 9/10
How many times will 10 go in 9? That is not possible, so you will write down zero and put a decimal point in front of it. Add zero to 9 to obtain 90. How many times will 10 goes in 90. That will be 9 times exactly .
 Therefore, 9/10 = 0.90.

4.  For 7/15
How many time will 15 go in 7? That is not possible, so you write down zero with a decimal point in front of it. Add zero to 7 to get 70. How many times will 15 go in 70? That will be 4 times remaining 10. Add zero to the remaining 10 to obtain 100. How many time will 15 go in 100? That will be will be 6 times, remaining 10.
Therefore, 7/15 = 0.46

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Answer is negative 2