What is 4.16 repeating as a fraction

4.16 =

Step-by-step explanation:

The given number is 4.16 repeating.

Here the whole number part is 4

4.16 repeating = 4 + 0.166...

Let's take the decimal part 0.166...

Let's assume x = 0.166...

Multiply by 10, we get

10x = 1.66...

Multiply by 100, we get

100x = 16.66...

Now let's subtract

100x - 10x = 16.66... - 1.66...

90x = 15

Divide both sides by 90, we get

x =

Now let's reduce the fraction by dividing both the numerator and the denominator by 15, we get

x =

Now let's add the whole number part 4 and the fraction

We can convert this mixed number to improper fraction

the correct functions are

h(x) = 3x + 2  

g(x) = 2^x

step-by-step explanation:

i proceed to calculate the different values ​​of k (x)

case 1)  k(x) = g(x) ∘ h(x)

g(x) ∘ h(x)=g(h(x))

k(x) = [2]^[3x + > is the option  4. k(x) = 2^(3x + 2 )

case 2)  k(x) = g(x) + h(x)

k(x) = [2^x]+[3x + 2]=2^x+3x+> is the option  1.) k(x) = 2^x + 3x + 2

case 3)k(x) = h(x) ÷ g(x)

k(x) =  [3x + 2]/[2^x]=3x/(2^x)+2/(2^x)=3x*(2^-x)+2^(1-x)

is the option  3.)   k(x) = (3x)2^(-x) + 2^(-x + 1 )

case 4)k(x) = g(x) - h(x)

k(x) =  [2^x]-[3x + 2]=2^x-3x-> is the option  2.) k(x) = 2^x - 3x - 2 

case 5)  k(x) = g(x) × h(x)

k(x) = [2^x]*[3x + > is the option  5.) k(x) = 2^x(3x + 2)

case 6)k(x) = h(x) ∘ g(x)

h(x) ∘ g(x)=h(g(x))

k(x)=3*[2^x]+> is the option  6. k(x) = 3(2^x) +2

sine

step-by-step explanation: