Mariana averaged 7474 on her first three history exams. the first score was 7777. the second score was 77 less than the third score. what did she score on the second and third exams

So the first score is 7777.

The second score was 77 less than the third score.

So here we first want to find the total score, by multiplying 7474 by 3. 

7474*3 = 22422

So the total test score was 22422.

So first subtract 7777 from 22422 to find the total score of the second and third exams.

22422 - 7777 = 14645

So the total test score of the two is 14645.

Now, since the second score was 77 less, there's a few ways to do it.

I'ma just do a random method.

Say the second score = x, and the third score = x+77.

x + x + 77 = 14645

2x = 14645 - 77

2x = 14568

/2     /2

x = 7284

So the second score was 7284.

The third is 77 more then that.

7284 + 77 = 7361

So her third exam score was 7361.

The answer to the question is d