Two cars leave the same location traveling in opposite directions. one car leaves at 3: 00 p. m. traveling at an average rate of 55 miles per hour. the other car leaves at 4: 00 p. m. traveling at an average rate of 75 miles per hour. let x represent the number of hours after the first car leaves. how many hours after the first car leaves will the two cars be 380 miles apart? enter an equation that can be used to solve this problem in the first box. solve for x and enter the number of hours in the second box.

Solution-

Two cars leave the same location traveling in opposite directions.

The first car leaves at 3 p.m and has a speed of 55 mph

The second car leaves at 4 p.m and has a speed of 75 mph

Let x hours after the first car leaves, the two cars are 380 miles apart from each other.

In this x hours, distance covered by the first car,

As the second car leaves at 4 p.m i.e 1 hour late as compared to the first car, so distance covered by the second car in (x-1) hours,

According to the question,

∴ After 3.5 hours from 3 p.m i.e at 6.5 p.m the cars will have a distance of 380 miles.

step-by-step explanation:

solution:

the given function is ,

      =

the three roots of this quadratic function is , 0 ,8 and 10.all the roots are real and rational.

if a quadratic equation is of the form ,

sum of the roots = a + b +c= 0+8+10=18=  

product of roots taken two at a time = a b + b c+ c a = 0+80+0=80 =  

product of roots = a b c = 0=  

there are 11 doors in a hall starting from 0 to 11.the entry in the hall is permitted through gate number 0 and exit is allowed through only gate number 8 and 10.so, three roots(0,8,10) of quadratic function is given by entry and exit route of this hall.