What is the solution of the system of equations? -3x-4y-3z=-7 2x-6y+2z=3 5x-2y+5z=9

Given equations have no solution

Step-by-step explanation:

Given -

Three set of equations -

We will now equate "x" in the first equation in terms of "y" and "Z" and put it in second equation -

We will substitute the value of y in the under given equation-

substituting the derived values in last equation, we get -

Hence, the  given equations have no solution

what is the original number? you forgot to add it.

c.

step-by-step explanation:

she should of added 9^2 and 12^2. that is because it is a^2+b^2=c^2. c^2 is the hypotenuse and should always be bigger than the other two numbers. which is why she should of added 9 squared and 12 squared together instead of 15 squared.