If r is the midpoint of qs, qr= 8x-51 and rs=3x-6, find qs.

 The required length of QS is 42 units.

Step-by-step explanation:  Given that R is the midpoint of QS, where

We are to find the length of QS.

Since R is the midpoint of the segment QS, so we must have

Therefore, the length of QS is given by

Thus, the required length of QS is 42 units.

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet