Find y'' by implicit differentiation. 5x3 + 2y3 = 1

For clarity, please write x^3 and y^3, not x3 and y3.

5x^3 + 2y^3 = 1

Differentiating all terms with respect to x, 

15 x^2 + 6y^2(dy/dx) = 0

Rearranging, 6y^2(dy/dx) = -15x^2
                                                                 -15x^2
Dividing both sides by 6y^2,     dy/dx = (which can be                                                                                     6y^2          reduced)

Now that you have dy/dx, differentiate again with respect to x.
Simplify your result.  This result represents   y".

Igxtfuvu cube b kisooaokajsvd wkisvhikbg