16. evaluate this piecewise function at x=-4 and x=4        x^2, if x_< -4f(x){  x^3, if -4< x_< 1          √x, if x> 1

I got it! Each function (x=) is solved separately. First is x= -4. You take that and replace all x's with -4. If the "if x..." is true you use the function in front to solve. In this case the x_<-4 is true for -4 equaling x. The function is front is x^2. So substitute the x for -4 and solve. -4^2 is 16.   Next you have the other one x=4. The function that goes with this one is the last one, substitute x for 4 and your answer is 2. The answers are 16 and 2. I hope this helps!

Letter c so sorry if i’m wrong ):