Write an equation of the line passing through point p(−8, 0) that is perpendicular to the line 3x−5y = 6

The equation of the line passing through point P(−8, 0) that is perpendicular to the line 3x−5y = 6 is 3y - 5x = 40

The equation of a line in point-slope form is expressed as:

where:

Given the equation 3x - 5y = 6

Rewrite in standard form:

-5y = -3x + 6

y = 3/5 x - 6/5

Slope m = 3/5

The slope of the line perpendicular to the line = -5/3

Given the point (-8, 0)

The equation of the line perpendicular will be expressed as:

Hence the equation of the line passing through point P(−8, 0) that is perpendicular to the line 3x−5y = 6 is 3y - 5x = 40

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answer: i oofed

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