Find a polynomial function of degree 3 with real coefficients that has the given zeros. -1, 2, -8 the polynomial function is f(x)=x^3+-10x-16

The zeros are -8, -1, 2, so you can write the function as f(x)=(x-(-8))(x-(-1))(x-2)=(x+8)(x+1)(x-2).

Expand:


The function is f(x)=x³+7x²-10x-16.
The missing value is 7.

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