The heights of the adults in one town have a mean of 66.8 inches and a standard deviation of 3.5 inches. what can you conclude from chebyshev's theorem about the percentage of adults in the town whose heights are between 56.3 and 77.3 inches?

At least 88.9% of the adults will have heights between 56.3 and 77.3 inches. First, determine how many standard deviations from the mean the lower and upper limits are. lower limit 66.8 - 56.3 = 10.5 10.5 / 3.5 = 3 standard deviations. upper limit 77.3 - 66.8 = 10.5 10.5 / 3.5 = 3 standard deviations. Chebyshev's theorem applies to all data sets and one of its claims is that at least 8/9 of the data points will lie within 3 standard deviations of the mean. Since you desire a percentage, do the division. 8/9 = .88888 = 88.9%

Ithink it is 7. 16