In the cash now lottery game there are 6 finalists who submitted entry tickets on time. from these 6 tickets, three grand prize winners will be drawn. the first prize is one million dollars, the second prize is one hundred thousand dollars, and the third prize is ten thousand dollars. determine the total number of different ways in which the winners can be drawn. (assume that the tickets are not replaced after they are drawn.)

120 total number of different ways in which the winners can be drawn.

Step-by-step explanation:

You have three prizes:

P1 - P2 - P3

There is no replacement for the tickets, so:

P1 can be any of the finalists. So there are 6 possible outcomes for P1.

P2 can be any of the finalists, bar P1. So there are 5 possible outcomes for P2.

P3 can be any of the remaining finalists, so 4 possible outcomes.

So

6 - 5 - 4

In all there are 6*5*4 = 120 total number of different ways in which the winners can be drawn.

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

believe it or not anna is correct good job anna give me a fist bump there u go gal