Point c ∈ ab , ab = 30m. point c is 1.5 times farther from point a than from point b. find ac and cb.

AC = 18 m

CB = 12 m

Step-by-step explanation:

Point C lies on line AB.

It is given, length of AB = 30 m and point C divides the line AB in such a way that point C is 1.5 times farther from point B.

Let Length of CB = x

Then length of AC = 1.5x

Now we know m(AB) = m(AC) + m(CB)

30 = 1.5x + x

30 = 2.5x

x =

x = 12 m

Therefore, AC = 1.5x = 12×1.5

                        = 18 m

CB = 12 m

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step-by-step explanation:

1. perpendicular

2. parallel

3. perpendicular