What is the answer to this question.

To divide these, you simply multiply the first fraction by the reciprocal of the second, meaning you flip the numerator and denominator. That means that we have (2x^2-5x-3)*(6x^2+11x-10)/(4x^2+12x+5)*(3x^2-11x+6). I'll factor one of the expressions, and I challenge you to do the rest!

For 2x^2-5x-3, we see that 2 multiplies the x^2, so we multiply 2 by -3 to get -6. We have to find 2 numbers that add to -5 but multiply to -6. With a bit of guess and check, we end up with -6 and 1, resulting in 2x^2-6x+x-3
= 2x(x-3)+1(x-3)= (2x+1)(x-3). Factor the rest, and you should have your answer! Good luck!

The correct answer is $90