Scientists at zoo recently studied an anaconda that weighs 8,643.2 ounces. the average weight of the common rat is 11.8 ounces. about how many times heavier is the anaconda than the common rat? explain why your answer is reasonable.

Step-by-step explanation:

Let the weight of anaconda will be n times the weight of rat.

We have been given that scientists at zoo recently studied an anaconda that weighs 8,643.2 ounces.The average weight of the common rat is 11.8 ounces.

We can represent our given information in an equation as:

Therefore, the anaconda is approximately 732.47 times heavier than the common rat.

Since both sides of equation are equal, therefore, our answer is reasonable.

step-by-step explanation:

12: 00 p.m. to 7: 00 p.m. is a total of 7 hours.

4: 00 p.m. to 7: 00 p.m. is a total of 3 hours.

this means that from 4: 00 p.m to 7: 00 p.m. this represents 3/7 of what was lost from 12: 00 p.m. to 7: 00 p.m.

after knowing this, after doing 11,600 - 6,800 = 4,800

4,800 represents 3/7 of what was lost for 7 hours.

we then divide 4,800 by 3 which gets 1,600.

because we know that 1,600 represents 1/7 of how much water was lost, we just have to multiply by 7, which gets 11,200.   after adding 11,200 to how much water was left at 7: 00 p.m. which was 6,800. 11,200 + 6,800 = 18,000

this means that the pool originally had 18,000 gallons in the pool.

you can also check your work by doing 18,000 - 4(1600), which becomes           1800 - 6400 which gets you 11,600.

a. 12.5 kg

step-by-step explanation:

f = ma

so

m = f/a = (2500 n)/(200 m/s²) = 12.5 kg

1 n = 1 kg·m/s²