Which graph below would match the situation described? a car travelling at 23 mi/h accelerates to 45 mi/h in 5 seconds. it maintains that speed for the next 5 seconds, and then slows to a stop during the next 5 seconds.

The graph shows that a car travelling at 23 mi/h accelerates to 45 mi/h in 5 seconds. It maintains that speed for the next 5 seconds, and then slows to a stop during the next 5 seconds is given by option C).

Given :

The following steps can be used in order to determine the correct graph that represents the giove situation:

Step 1 - The kinematic equation for the velocity is given by:

v = u + at   --- (1)

Step 2 - According to the given data, the initial velocity is 23 mi/hr, the final velocity is 45 mi/hr and the time to accelerate is 5 seconds.

Step 3 - Substitute the known terms in equation (1).

45 = 23 + 5a

22 = 5a

a = 4.4

Step 4 - The final velocity is zero because at the end of 15 seconds.

Therefore, the correct graph that shows the given situation is option C).

For more information, refer to the link given below:

link

u what ?

step-by-step explanation:

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0