How would you solve (3a-4)^2? according to my teacher the answer is (3(a-1))^2 = 9a^2 - 18 a + 9

(3a - 4)^2 =
(3a - 4)(3a - 4) =
3a(3a - 4) - 4(3a - 4) =
9a^2 - 12a - 12a + 16 =
9a^2 - 24a + 16 <== I am not getting what ur teacher got

is the problem written correctly ?
Because (3a - 3)^2 = 9a^2 - 18a + 9

Ifound this on google “a skewed (non-symmetric) distribution is a distribution in which there is no such mirror-imaging. a "skewed right" distribution is one in which the tail is on the right side. a "skewed left" distribution is one in which the tail is on the left side. the above histogram is for a distribution that is skewed right.” i hope this you for what your looking for