Calculate the area of triangle abc with altitude cd, given a (6, 0), b (1, 5), c (2, 0), and d (4, 2). 5 square units 8 square units 10 square units 13 square units < -my answer can someone tell me if my answer was right?

1).  yes, someone can tell you.

2).  your answer is not right.



the altitude of the triangle is cd (2,0) to (4,2).
its length is the square root of (2-0)² + (4-2)² = √(2² + 2²) = √8  =  2√2

the base of the triangle is ac (6,0) to (1,5).
it's length is the square root of (1-6)² + (5-0)² = √(-5² + 5²) = √(50 = 5√2

the area of the triangle is  (1/2) (base) (height) =
                                            (1/2) (5√2) (2√2) =
                                            (1/2) (10 * 2) =
                                            (1/2) (20)  =  10 units

2xy/9 is the answer to this problem