Could someone guide me through this one plz a system of two equations is shown below: equation c: a = 4b + 5 equation d: a = 6b − 2 what value of a can be substituted into equation d to solve the system of equations? 4b + 5 6b − 2 4b 6b

the answer is 4b +5

Step-by-step explanation:

a = 4b +5  > first equation

a = 6b - 2  > second equation

Given the first equation a= 4b +5

Here 'a' is alone

In substitution method we substitute the first equation in second equation

So we substitute a= 4b+5 in the place of 'a' in second equation

The value 4b+5 can be substituted in the second equation to solve the system of equations

answer: solve 5\cdot 2^x=2405⋅2  

x

=2405, dot, 2, start superscript, x, end superscript, equals, 240.

solution

to solve for xxx, we must first isolate the exponential part. to do this, divide both sides by 555 as shown below. we do not multiply the 555 and the 222 as this goes against the order of operations!

\begin{aligned} 5\cdot 2^x& =240 2^x& =48 \\ \end{aligned}  

5⋅2  

x

2  

x

​    

=240

=48

​

step-by-step explanation: