Devin brought his snail collection to school. he has 10 snails. how could he put them into 2 tanks so two classes could see them? write equations for all the possible ways. one of the ways is given. explain how you know have found all the ways one of the ways is given. explain how you know have found all the ways

Step-by-step explanation:

Total no. of snails Devin has = 10

We have to divide these into two tanks.

Let m be the number of snails in tank 1 and let n be the number of snails in tanks 2.

There are various ways in which these snails could be divided.

We can define an equation that would help us to divide the snail:

Ways in which snail can be divided:

When there is 1 snail in tank 1 and other 9 in tank 2 that is m = 1, n = 9

Other ways could be

m =2, n = 8

m = 3, n= 7

m = 4, n= 6

m = 5, n = 5

m = 6, n = 4

m = 7, n = 3

m = 8, n = 2

m = 9, n = 1

We know we have found all the combinations because there are no other possible combinations for sum to be 10.

d) by the cross product property, ab^2 = bc multiplied by ad

step-by-step explanation:

we are given

in the given triangle abc

angle a is 90° and segment ad is perpendicular to segment bc

we can see that

triangle(abc) and triangle(abd) are similar because they have common side and same angle (90 degree)

so, triangles(abc) and abd are similar

since, they are similar

so, the ratio of their sides must be equal

we get

now, we can cross multiply

and we get

so, this could be step to prove it

you didn't give me the choices, so i will just give you the graph so you can look at your choices and choose the right one.