Mathematics, 01.07.2019 09:20 cxxcee
Solve cos x + sq. root of 2 = - cos x for x over the interval {0,2pi]. a) x = 3pi/4 b) x = 3pi/4 + 2npi c) x = 3pi/4 and 5pi/4 d) x = pi/4 and 7pi/4
Answers: 1
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Solve cos x + sq. root of 2 = - cos x for x over the interval {0,2pi]. a) x = 3pi/4 b) x = 3pi/4 +...
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