After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are a'(6, 3), b'(–2, 1), and c'(1, 7). what are the coordinates of the vertices of the pre-image? a - b - c -

Given coordinates of the transformed image:

A'(6, 3),

B'(–2, 1), and

C'(1, 7).

We need to find the coordinates of the pre-image A, B and C.

The rule for rotation of 90° about the origin is (x,y) ---> (-y,x).

But we need to find the coordinates of the vertices of the pre-image.

So, we need to apply rule (-y,x) >(x,y).

Applying rule,

A'(6, 3) > A (3, -6)

B'(–2, 1) > B(1, 2)

C'(1,7) > C (7, -1).

The coordinates of the preimage of is A(-3, 6), B(-1, -2), C(-7, 1)

Transformation is the movement of a point from its initial location to a new location. Types of transformation are reflection, rotation, translation and dilation.

If a point A(x, y) is rotated 90° clockwise about the origin, the new point is at A'(y, -x)

The coordinates of the preimage of is A(-3, 6), B(-1, -2), C(-7, 1)

Find out more on transformation at: link

y=mx+b

step-by-step explanation:

m slope, b y-intercept

your question is incomplete, write all the numbers in the sequence that it tells you.  

step-by-step explanation: