The heat in the house is set to keep the minimum and maximum temperatures (in degrees fahrenheit) according to the equation |x – 72.5| = 4. what are the minimum and maximum temperatures in the house? 72.5°f and 76.5°f 68.5°f and 76.5°f 70.5°f and 74.5°f 72.5°f and 74.5°f

B : 68.5°F and 76.5°F

Step-by-step explanation:

The equation has absolute value in it, meaning that the two equations for the two answers could be seen as "x-72.5=4" and "72.5-4=x".

x-72.5=4   :

72.5+4=x

72.5+4=76.5=x

76.5=x

72.5-4=x   :

72.5-4=68.5=x

68.5=x

answer: ratio of volume of cone (with 3 times the height and equal diameter) to volume of cylinder is 2 to 1. the value of π is not used.

step-by-step explanation:

radius is diameter/2 = 4.

area of circle is π r^2.

volume of cylinder is height × area of base = hπr^2 = 3(4^2) π = 48π cubic inches.

not knowing the formula for volume of cone, i calculate it using calculus (which is for calculating things).

volume of cone is integral 0 to h area(y) dy. area(y) is π r(y)^2. r(y) runs r to zero as y runs zero to h, r(0) = r, r(h) = 0.

r(y) = r - r/h y

area(y) = π (r - r/h y)^2 = π (r^2 - 2r^2y/h + r^2y^2/h^2) = π r^2(1-2y/h+y^2/h^2)

antiderivative area(y) = π r^2 (y-y^2/h+y^3/(3h^2))

integral 0 to h = π r^2(h-h^2/h+h^3/(3h^2) - (0)) = π r^2(h - h + h/3) = π r^2(h/3) = π/3 r^2 h

volume of this cone is π/3(4^2)18 cubic inches.

= 6 16 π = 96π cubic inches.

cone has twice the volume, 96/48.

cone height is 6 times the cylinder.

ratio of volume formula: π r^2 cancels.

cone over cylinder ratio is 6h/3 to h, 2 to 1.

no solution

step-by-step explanation:

there is not enough information in the problem to solve.