Mathematics, 01.07.2019 03:20 elf55
Using a directrix of y = 2 and a focus of (3, −4), what quadratic function is created? (5 points) f(x) = one twelfth (x − 3)2 − 1 f(x) = − one twelfth (x − 3)2 − 1 f(x) = − one sixth (x + 3)2 + 1 f(x) = one sixth (x − 3)2 + 1
Answers: 1
![\bf \begin{cases} h=3\\ k=-1\\ p=-3 \end{cases}\implies (x-3)^2=4(-3)[y-(-1)] \\\\\\ (x-3)^2=-12(y+1)\implies \cfrac{(x-3)^2}{-12}=y+1 \\\\\\ -\cfrac{1}{12}(x-3)^2-1=y](/tpl/images/0037/2205/ace38.png)
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Using a directrix of y = 2 and a focus of (3, −4), what quadratic function is created? (5 points) f...
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