Agrain silo has a diameter of 4.4 meters. the height of its cylindrical portion is 6.2 meters. what is the approximate total volume of the silo? use 3.14 for π and round the answer to the nearest tenth of a cubic meter. 37.1 m3 71.9 m3 116.5 m3 130.8 m3 answer is c, because no one has answered

Option: C is the correct answer.

The volume of grain silo is:

116.5 m^3

Step-by-step explanation:

A grain silo has a diameter of 4.4 meters. The height of its cylindrical portion is 6.2 meters.

A grain silo is made up of a cylinder and a hemisphere over it.

The radius(r) of cylinder is:4.4/2=2.2 meters.

Height(h) of cylinder is:6.2 meters.

Now volume of grain silo is:

Volume of cylinder(V)+ Volume of hemisphere(V').

Volume of cylinder is calculated as:

and Volume of hemisphere is calculated as:

Hence, volume of grain silo is:

Hence, the volume of the grain silo to the nearest tenth of cubic meter is:

116.5 m^3

let's add {f(x)=x+1}f(x)=x+1 and {g(x)=2x}g(x)=2x together to make a new function.

f(x)+g(x) =(x+1)+(2x)=x+1+2x=3x+1

let's call this new function hh. so we have:

{h(x)}={f(x)}+{g(x)}{=3x+1}h(x)=f(x)+g(x)=3x+1

we can also evaluate combined functions for particular inputs. let's evaluate function hh above for x=2x=2. below are two ways of doing this.

method 1: substitute x=2x=2 into the combined function hh.

h(x)

h(2)

​    

=3x+1

=3(2)+1

=7

​ since h(x)=f(x)+g(x)h(x)=f(x)+g(x), we can also find h(2)h(2) by finding f(2) +g(2)f(2)+g(2).

first, let's find f(2)f(2):

f(x)

f(2)

​    

=x+1

=2+1

=3

​  

now, let's find g(2)g(2):

g(x)

g(2)

​    

=2x

=2⋅2

=4

​  

so f(2)+g(2)=3+4=\greend7f(2)+g(2)=3+4=7.

notice that substituting x =2x=2 directly into function hh and finding f(2) + g(2)f(2)+g(2) gave us the same answer!

with btw u said 100pts but it clearly says

i answerd and just got 10pts

no hate