Can someone me with this problem

Step 1: learn to draw a free-body diagram.  Read your school notes or look up a web site on the subject.
Step 2: Denote the angle of the ramp with the horizontal as theta=tan^(-1)(20/30)=33.69 degrees (approx.)
Step 3: denote the mass of the object as m=100 lb-mass.
Step 4: find force due to mass and gravity = -100g = -100 lb-force. (downwards), denoted by the vector F=(0,-100) lb-force.
Step 5: resolve force along incline:
Force parallel to incline = F1 = -100(cos(theta))
=-83.21 lb-force (negative => down the incline)
Step 6: resolve force perpendicular to incline
= F2 = -100(sin(theta)
=-55.47 lb-f  (-ve =>into the incline)

By the way, this question is not calculus 3, but more mechanics, or physics.  You have a better chance of getting answers if posted under "physics".

55. i don’t no. but zhongshan