I need help with this question please. This is non graded.

Given:

vertex : (-5, -10)

Point : (0, 15)

A quadratic equation can be written in its vertex form as:

Where (h,k) is the coordinate of the vertex and a is the constant multiplier

For this problem,

Hence, we can write:

Since the point (0, 15) lies on the curve, we can substitute and solve for a:

Hence, in vertex form, the quadratic equation is:

Option C

last option

step-by-step explanation:

given that δdef is right and isoceles,

assuming that side df is the hypotenuse means that de an ef are the other 2 sides that intersect at 90° and are of equal length.

because they are of equal length, we can say that they are congruent

because they intersect at 90°, their slopes must be opposite reciprocals.

only the last option satisfies these conditions.

answer: 1 + 1 = 11

step-by-step explanation: