Maria invested $5000, some at 6% and some at 9%. If she wins $393 annual interest how much is invested in each account.

Ok, so

We could solve this problem using a system of linear equations as follows:

x = amount invested at 6%

y = amount invested at 9%

We are given two numbers in the problem:

$5000 = total money invested in both accounts

$393 = total interest earned in both accounts

Then we could write:

This system can be solved using sustitution:

Replacing:

And y = 5000 - x, which is 5000 - 1900, and that is 3100.

We obtain that the solution of the system is:

Therefore, there was invested $3100 in the account at 9% and 1900 in the account at 6%.

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