Please help me
True or false?
I accidentally answered it but
ignore it just please help

Step-by-step explanation:

You are correct in saying false

well, the cheap answer is, linear expressions have one variable and some coefficient in front of it, like 3x or 2y + 3, or (1/4)x - 15 or such, however, a LINEar expression when drawn, yields a LINE, not a curve or such, and that only happens if the variable's exponent is 1, not more than 1, if the variable's exponent is higher, then is a curve of kinds,

so such expressions like -13xy, which has the product of two variables, or 7y³ - 2 or 4x⁵ + 9, are curvy lines.

(0,-3) see attached graph

step-by-step explanation:

a. to solve the system, graph the two equations.

x = y+3 becomes y=x-3 has m=1/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move up 1 unit and 1 unit to the right. plot a point and connect.

y=-4x+3 has m =-4/1 and b=-3. start at (0,-3) on the y-axis and plot a point. then move down four units and to the right 1 unit. plot a point and connect.

the solution is the point (x,y) where the two lines intersect. by the graph below it is (0,-3).

b. to solve by substitution, substitute y = -4x-3 into x= y+3

x= (-4x-3) +3

x=-4x

5x=0

x=0

now substitute x = 0 back in to find y.

y= -4(0)-3

y=0-3

y=-3

solution is (0,-3)

c. use elimination by adding the equations together.

x-y=3

4x+y=-3

5x=0

x=0

then substitute into one equation to find y.

y=-4(0)-3

y=-3

i did it myself and i got 4.2 (b) hope its right

step-by-step explanation: