An urn contains three white balls and two black balls. A player draws randomly and successively three balls from this urn, respecting the following rule: In each draw: if the drawn ball is black, he replaces it back in the urn; if it is white, he doesn't replace it back in the urn.
1) Calculate the probability of drawing, in the following order: one black ball, one black ball then one white ball.
2) Show that the probability of obtaining one white ball only, among the three drawn balls,, is equal to 183/500

can someone please please help me with this