Find the area of a regular pentagon with a radius of 9 yds. show all six steps.

  192.6 square yards

Step-by-step explanation:

The area of a regular pentagon can be found using the formula for any regular polygon.

  A = (n/2)r²·sin(360°/n) . . . . radius r, n sides

For a pentagon, the number of sides is 5, so this becomes ...

  A = 2.5r²·sin(72°)

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Using the given value of radius, the area is ...

  A = 2.5(9 yd)²·sin(72°) = 2.5 · 81 · 0.951057 yd²

  A ≈ 202.5 · 0.951057 yd²

  A ≈ 192.589 yd²

The area of the pentagon is about 192.6 square yards.

Additional comment

We're not sure what "six steps" you're supposed to follow. The necessary steps appear to be ...

Here, the formula for a pentagon can be simplified somewhat by precomputing the value of 2.5×sin(72°) ≈ 2.37764129074. Then the formula for the area is ...

  A = 2.37764129074·r² . . . . . area of regular pentagon with radius r

see below

step-by-step explanation:

7.   there are 10 data points in the set.   the middle point is between 5 and 6.   the middle point in the top half is 8   and the middle point in the bottom half is 3. to find the iqr , take point 8 and subtract point 3

mid term   point 8 = 100   point 3 = 88

iqr = 100-88 = 12

final   point 8 = 93   point 3 = 78

iqr = 93 - 78 = 15

the final has the greatest iqr

6.   b - there is a high data value that causes the data set to be asymmetrical for the males: the data for males are high and asymmetrical .   there is an outlier for the males that skews the data

5.   the   iqr is a better measure of spread for the movies and basketball games.   since the basketball game has an outlier, we do not want to use standard deviation for measurement.  

3.   the exam median is much higher than the class median.   the median line is farther to the right on the exams

2.   there is no way to tell what the means are from the box and whisker plots.  

the volume is the product of the area of the base, 3x(3x+4), and the height, 3x-1

step-by-step explanation: