Number of solutions of quadratic equations

Discriminant = 120

Number of x intercepts = 2

Explanation:

The equation is of the form ax^2+bx+c with:

a = -7

b = 8

c = 2

The discriminant is

d = b^2 - 4ac

d = 8^2 - 4(-7)(2)

d = 64 + 56

d = 120

The discriminant is positive, meaning there are 2 different x intercepts.

If d = 0, then we'd have only one x intercept.

If d < 0, then there wouldn't be any x intercepts.

i found two solutions,   n = 2 • ± √3 = ± 3.4641

step-by-step explanation:

answer: r there any options?

step-by-step explanation: