Given that Cos0=5/13,find a)Tan0,b)Sin0,c)Sec0,d)Co sec0,e)Cot0,

cos θ = Adjacent/ hypotenuse

cosθ= 5/13

a²+b²= c²

a² + 5² = 13²

a² = 13² - 5²

a² = 144

a=√144

a= 12

a is the opposite = 12

b is the Adjacent = 5

c is the hypotenuse = 13

a) tan θ= opposite/Adjacent

tan θ = 12/5

b) sin θ= opposite/ hypotenuse

sinθ= 12/13

C) sec θ= hypotenuse / Adjacent

sec θ= 13/5

d) cscθ= hypotenuse /opposite

cscθ= 13/12

e) cotθ=Adjacent/ opposite

cotθ= 5/12

answer: do we write it

step-by-step explanation: