The populations of two cities after t years can be modeled by -150t+50,000 and 50t+75,000 . What is the difference in the populations of the cities when t=4 ?

The difference in the populations of the cities when t=4 is 25,800.

Step-by-step explanation:

Given equations each of the city:

-150t+50,000

and

50t+75,000

To find the difference between the population when t=4, we first have to solve both equation when t=4.

For both equations, substitute 4 into t:

-150(4) + 50,000 = 49,400

50(4) + 75,000 = 75,200

Now subtract 49,400 from 75,200 and you get 25,800.

The difference in the populations of the cities when t=4 is 25,800.

:

step-by-step explanation:

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this