Write an equation for a parabola with vertex at (1,3) that passes through (-2,-15)

➢ Vertex form of a parabola is

y = a(x-h)^2 + k

where

(h,k) is the vertex.

Since the problem gives you the vertex we can plug it in:

y = a(x-1)^2 + 3

Now, we plug in the given point and solve for a:

➾ -15 = a(-2-1)^2 + 3

➾ -15 = a(-3)^2 + 3

➾ -15 = a(9) + 3

➾ -18 = a(9)

➾ -2 = a.

➢ So, our equation is now:

y = -2(x-1)^2 + 3

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step-by-step explanation:

the correct answer is

c. 4

step-by-step explanation:

the given polynomial is

the degree of the polynomial is the highest exponent which is 4.

the -4 is called the leading coefficient.

this polynomial has only one term so it is a monomial.

the correct answer is option c.