5. A box contains 4 white balls and 6 yellow balls. A ball is drawn at random from the box and is not replaced. What is the probability that both balls are white? 8/45
3/25
4/25
2/15

2/15

Step-by-step explanation:

Given:

A box contains 4 white balls and 6 yellow balls. A ball is drawn at random from the box and is not replaced. What is the probability that both balls are white?

8/45

3/25

4/25

2/15

Solve:

Knowing that total = 10 { 4 white balls and 6 yellow balls}

P(first white)=4/10=2/5 { 4 out of 10 balls are white}

P(second white)=3/9=1/3 { 3 out of 9 balls are white; Since no replaced}

P(both white)=2/5 × 1/3=2/15

Hence, Answer = 2/15

Lenvy~

answer: i would say b

step-by-step explanation:

with the way the question is worded, i believe b is the answer

the cost of the apple depends on the weight

step-by-step explanation:

always plug in x. in this case, x equals 4.

i'm going to first solve 4(2+3x)

1) 4(2+3(4)) use pemdas to solve.

i'm going to multiply whats in the parenthesis first, so 3 times 4=12.

2)4 (2+12) i'm then going to multiply 4 by both numbers in the parenthesis (because multiplying comes before adding)

4 times 2= 8.   4 times 12= 48

4) (8+48)= 56 (answer)

i'm then going to solve 8+12x and plug in 4 for x.

1) 8 +12(4)

multiplying comes before adding, so i'm gonna multiply 12 and 4.

12 times 4= 48.

2) 8+48=56

both equal the same!