It was 47 degrees when Tanya got out of bed this morning. If the temperature rose 18 degrees by lunchtime, what temperature was it then?

65˚

Add 47 and 18 to get the temperature by lunchtime

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.

there is no question content here, but you for the free points! : d