How can the area of this triangle be determined by forming a rectangle? Select from the drop-down menus to correctly complete the statements.

Copy and rotate the triangle and place it next to the existing triangle to form a rectangle. The length of the rectangle is
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units. The width of the rectangle is
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units. The area of the rectangle is
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square units.

The area of the triangle is half the area of the rectangle, so the area of the triangle is
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square units.

Right triangle on a grid. One side of the triangle is horizontal and has a length of 5 units. Another side is vertical and has a length of 4 units.

x =±sqrt(1/3)

step-by-step explanation:

x+4/6x=1/x

multiply each side by 6x to get rid of the fractions

6x*(x+4/6x)=1/x*6x

distribute

6x^2 +4 = 6

subtract 4 from each side

6x^2 +4-4 = 6-4

6x^2 =2

divide by 6

6x^2/6 = 2/6

x^2 = 1/3

take the square root of each side

sqrt(x^2) = ±sqrt(1/3)

x =±sqrt(1/3)

the correct answer option is (2x-3)(2x+3).

step-by-step explanation:

we are given the following expression and we are to factorize it:

we are to find such factors that when multiplied they give a result of 36 (9 x 4 = 36) and when added they give a result of 0.

the two such factors of 36 are negative six and postive six.

factorizing the given expression to get:

therefore, the correct factorization of is (2x-3)(2x+3).

i think its a.

hope this