A person bought some articles at the rate of 5 per rupee (₹) and the same number of articles at the rate of 4 per rupee (₹). He mixed both the types and sold them at the rate of 9 for ₹2. In this business, he suffered a loss of ₹3. The total number of articles bought by him was: a. 1090

b. 1080

c. 540

d. 545

Step-by-step explanation:

Lets assume the number of articles was x.

Half of the articles was bought at the price 1/5 rupee each and the other half was  bought at the price 1/4 rupee each.

Cost of articles:

Money made after sale is:

The difference is 3 rupees:

Correct choice is B

70

step-by-step explanation:

step-by-step explanation: given equation a = h(b 1+b 2)

also we are given values of a, h and b 1 as :

a = 16, h = 4, and b 1 = 3.

in order to solve it for b 2, we need to plug the given values of   a, h and b 1 .

therefore, plugging values of   a, h and b 1   in given equation, we get

16 = 4( 3 + b 2)

first dividing both sides by 4, we get

4 = 3 + b 2

subtracting 3 from both sides, we get

4 -3 = 3 -3 + b 2

1 = b 2.