Please help me with this

  (b)  y -5 = 3/4(x -6)

Step-by-step explanation:

The point-slope form of the equation for a line with slope m through point (h, k) is ...

  y -k = m(x -h)

Your graph has two points marked: (-2, -1) and (6, 5). Even if you don't know the slope, these tell you the form of the equation will be ...

  y +1 = m(x +2) . . . . no match

  y -5 = m(x -6) . . . . matches choice B

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If you like, you can figure out the slope to be ...

  m = (y2 -y1)/(x2 -x1)

  m = (5 -(-1))/(6 -(-2)) = 6/8 = 3/4

All the answer choices agree that this is the slope of the line.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

answer: 2530

hope this