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Mathematics, 14.03.2022 15:00 ayandjay01

The work of a student to solve the equation 3(3x βˆ’ 4) = 8 + 2x + 5 is shown below: Step 1. 3(3x βˆ’ 4) = 8 + 2x + 5 Step 2. 6x βˆ’ 7 = 13 + 2x Step 3. 6x βˆ’ 2x = 13 + 7 Step 4. 4x = 20 Step 5. x = 5 In which step did the student first make an error and what is the correct step? (1 point) Step 2, 9x βˆ’ 12 = 13 + 2x Step 2, 9x βˆ’ 4 = 2(6 + x + 3) Step 3, 6x + 2x = 13 + 7 Step 3, 6x βˆ’ 2x = 13 βˆ’ 7

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The work of a student to solve the equation 3(3x βˆ’ 4) = 8 + 2x + 5 is shown below: Step 1. 3(3x βˆ’ 4)...
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