For an object whose velocity in ft/sec is given by v(t) = −t2 + 2, what is its displacement, in feet, on the interval t = 0 to t = 2 secs? 1.333
2.438
2.667
−4

1.333

Step-by-step explanation:

We know that the displacement function is the integral of the velocity function. We are also given our bounds, 0 seconds to 2 seconds.

x(t) = = -t³/3 + 2t (evaluated from zero to two)

= [-2³/3 + 2(2)] - [-0³/3 + 2(0)] = 4/3 = 1.333...

answer:

125 yards

explanation:

75+50=125. that is my answer

d.) yes, because the volume of the cone is greater than the volume of the sphere

step-by-step explanation: