PLEASE HELP ! POINTS AND BRAINLIEST !!! Anything helps!!

According to Masterfoods, the company that manufactures M&M's, 12% of peanut M&M's are
brown, 15% are yellow, 12% are red, 23% are blue, 23% are orange and 15% are green. You
randomly select six peanut M&M's from an extra-large bag of the candies. (Round all probabilities
below to four decimal places; i. e. your answer should look like 0.1234, not 0.1234444 or 12.34%.)

Compute the probability that exactly five of the six M&M’s are orange.

Compute the probability that four or five of the six M&M’s are orange.

Compute the probability that at most five of the six M&M’s are orange.

Compute the probability that at least five of the six M&M’s are orange.

If you repeatedly select random samples of six peanut M&M’s, on average how many do you expect to be orange?

With what standard deviation?

nothjing

step-by-step explanation:

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.

what graph

step-by-step explanation:

delaney would like to make a 5lb nut mixture that is 60% peanuts and 40% almonds.

she has several pounds of peanuts and several pounds of a mixture that is 20% peanuts and 80% almonds.

let 'p' represent the number of pounds of peanuts needed to make the new mixture, and  

let 'm' represent the number of pounds of the 80% almond-20% peanut mixture.

:

p + m = 5

therefore

m = (5-p)

write an equation based on the percent of peanuts

1p + .2m = .6(5)

replace m with (5-p)

p + .2(5-p) = .6(5)

p + 1 - .2p = 3

p - .2p = 3 - 1

.8p = 2

p = 2/.8

p = 2.5 lbs of peanuts required

then

5 - 2.5 = 2.5 lbs of the peanut/almond mixture required

:

a) what is the system that models this situation?

p + m = 5

1p + .2m = .6(5)