1.) WHat are the real zeros of the function y=x(x-2)(x+3)

2.) Find all of the solutions of the equation
x^3 -x^2 +5x - 5 = 0

Problem 1

The roots are x = 0, x = 2, x = -3

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Explanation:

The term "root" is another way of saying "zeros of a function" or "x intercept".

To find the roots, set each factor equal to zero and solve for x.

x-2 = 0 solves to x = 2, while x+3 = 0 solves to x = -3

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Problem 2

Roots are x = 1, and

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Explanation:

Factor by grouping

x^3 - x^2 + 5x - 5 = 0

(x^3 - x^2) + (5x - 5) = 0

x^2(x - 1) + 5(x - 1) = 0

(x^2 + 5)(x - 1) = 0

x^2 + 5 = 0 solves to the roots and

x-1 = 0 solves to x = 1

Note:

1) Wat are the real zeros of the function y=x(x-2)(x+3):

To find the x-intercept, set y = 0:

x( x -2 ) ( x + 3) = 0

Apply the Zero Product Property:

x - 2 = 0 or x + 3 = 0

x = 2 or x = -3

Find the union of solutions:

x = 0 or x = 2 or x = -3

2) Find all of the solutions of the equation

x^3 -x^2 +5x - 5 = 0

x = 1 or no real solution

Apply grouping:

Factor out common factor:

Factor out -->

Apply zero product property:

or

x - 1 = 0

Rearrange variables to the left side of the equation--> x=1 or no real solutions.

robert puts 2 in each row

i think it would be 43 movies that would have to be watched.

step-by-step explanation:

think about it. for the second plan, every month is 8 dollars. 8 x 12= 96. so thats the number for the second plan. now for the first plan, its annual meaning you have to pay 10 dollars every year. so now you have to get an equivalent amount of 86 since 96-10=86. 86 divided by 2 since every movie costs 2$ then you would have to watch 43 movies a year to get the same as the second plan. i really hoped this . have a wonderful day as well!