Type the correct answer in each box. If necessary, use / for the fraction bar(s). John recorded the number of cars passing a traffic signal at intervals of 2 minutes. He plotted his data on this graph.

The slope of the line is
, and the y-intercept is

.

Slope: 20/7

Y-intercept: 0

Step-by-step explanation:

Hello!

This is a regular graph, and we can find out several things from it, including slope and y-intercept.

The slope is basically how steep or flat the line is. The more flat it is, the bigger the slope. The more steep it is, the more smaller the slope. We can find the slope by using rise over run, seeing how many values it rises over how many values it runs over the x-axis.

The y-intercept is basically where the line starts from in the y-axis. The y-axis is a vertical line usually at the left most area.

To find out the slope, we can see the best fit blue line, and we have to find the most accurate slope. In this problem, the line doesn't go through perfectly with the grid at until around (14, 40). Don't get mistaken for (2,5)! It's not an accurate slope. Since it goes UP and rises 40 and 'runs' 14 units, the slope is that but simplified.

\frac{40}{14} =\frac{20}{7}

The y-intercept is where the line starts from the y-axis, where it labels 'cars'. As you can see, the blue line starts at zero, so there is no y-intercept.

To take it further, the equation of the line is y=mx+b, where m is the slope and b is the y-intercept. In this problem, the equation would be

y=x.

Hope this helped!

for the friend request.

when a figure, such as triangle (xyz) is reflected over the line y = x to create x'y'z' the x-coordinates and y-coordinates of the original image (pre-image) will be reversed for the image. (e.g., (x, y) > (y, x)) this means that the pre-image position of the x- and y-coordinates switch places which in turn provides a mirror like image of the original xyz.  

i notice that when i draw a line segment from x to x', that the points are parallel from each other -- they are exactly across from each other and do not intersect with any other points.  

yes, think i would see the same characteristic if you drew the line segment connecting y with the reflecting line and then y' with the reflecting line because of the essence of reflections. because it is a mirror image, each point was effected the same way which leads me to conclude that they same would apply to y and y'.