Consider the graph of y=f(x) shown below in blue. Sketch the graph of f′(x) by dragging the red points along the vertical direction to adjust the slope of the black tangent lines, shown at selected locations on the graph of f(x). The y-coordinate of each of the red points is a measure of the derivative of f(x) at the corresponding x value. After you have performed these adjustments at all locations, the red points will represent your answer for the outline of the graph of f′(x).

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step-by-step explanation:

i am currently in the exact same situation rn. algebra2/adv algebra is killing

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°