estimate the perimeter of a school chalkboard, measuring 76 cm by 46 cm. Give your answer to the nearest ten

260

Step-by-step explanation:

76 rounded to 1 s.f. is 80

46 rounded to 1s.f. is 50

80+50+80+50= 260

Hope this helps!

240 cm (to the nearest ten)

Step-by-step explanation:

perimeter of a rectangle = 2W + 2L

where W is the width and L is the length

To estimate the perimeter, first round the components to the nearest ten then carry out the calculation.

Given:

⇒ estimated perimeter = 2 x 50 + 2 x 80 = 100 + 160 = 260 cm

Alternatively, to calculate the actual perimeter and then round the answer to the nearest ten:

⇒ actual perimeter = 2 x 46 + 2 x 76 = 92 + 152 = 244 cm

⇒ perimeter = 240 cm (to the nearest ten)

step-by-step explanation:

c

step-by-step explanation:

there is vertical asymptote at x = 2 and x = 0

vertical asymptote occurs at the points where the denominator is 0. so we can say that

x = 2 occurs when there is a factor (x-2) in the denominator, and

x = 0 occurs when there is a factor "x" in the denominator

thus, the denominator of the equation would have "x * (x-2)", this is option c only. that's the correct answer.