Help with the answer please

A is the answer

Step-by-step explanation:

I hope it helps sorry kung mali

Step-by-step explanation:

know, ∠BGA = 90

In right angled triangle BGA

AB = 12 cm (diameter of circle)

⇒ (AB)2 = (AG)2 + (BG)2

⇒ 122 = 82 + (BG)2

⇒ BG = 4√5

In right angled triangle BCG

Let CG be x cm.

⇒ (BC)2 = (CG)2 + (BG)2

⇒ (BC)2 = x2 + (4√5)2 (1)

As we know,

⇒ (BC)2 = CG × CA (2)

From equation (1) and equation (2)

⇒ x2 + (4√5)2 = x × (x + 8)

⇒ x2 + (4√5)2 = x2 + 8x

⇒ 8x = 80

⇒ x = 10 cm

From equation (2)

⇒ (BC)2 = CG × CA

⇒ (BC)2 = 10 × 18 = 180

⇒ BC = √180 = 6√5

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

answer:

f(5/2) = 10/3

i hope this you!